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12(3x^2+5x-2)=0
We multiply parentheses
36x^2+60x-24=0
a = 36; b = 60; c = -24;
Δ = b2-4ac
Δ = 602-4·36·(-24)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-84}{2*36}=\frac{-144}{72} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+84}{2*36}=\frac{24}{72} =1/3 $
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